The specific heat of alcohol is about half th | vedclass

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(B) Let $m$ be the mass of both alcohol and water. Let $S_A$ and $S_W$ be the specific heats of alcohol and water,respectively. We are given $S_A \app

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Closer to $T_W$ than $T_A$

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(B) Let $m$ be the mass of both alcohol and water. Let $S_A$ and $S_W$ be the specific heats of alcohol and water,respectively. We are given $S_A \approx 0.5 S_W$,which implies $S_W > S_A$.When mixed,the heat lost by the hotter substance equals the heat gained by the colder substance: $m S_A (T_f - T_A) = m S_W (T_W - T_f)$ (assuming $T_W > T_A$).Simplifying,$S_A T_f - S_A T_A = S_W T_W - S_W T_f$.$T_f (S_A + S_W) = S_W T_W + S_A T_A$.$T_f = \frac{S_W T_W + S_A T_A}{S_W + S_A}$.Since $S_W > S_A$,the final temperature $T_f$ will be weighted more towards the temperature of the substance with the higher specific heat,which is water $(T_W)$.

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